# In the Health ABC Study, 547 subjects owned a pet and 1971 subjects did not. Among the pet owners, there were 300 women

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Question: In the Health ABC Study, 547 subjects owned a pet and 1971 subjects did not. Among the pet owners, there were 300 women; 982 of the non-pet owners were women. Find the proportion of pet owners who were women. Do the same for the non-pet owners. (Be sure to let Population 1 correspond to the group with the higher proportion so that the difference will be positive. Round your answers to three decimal places.)

Give a 95% confidence interval for the difference in the two proportions. (Do not use rounded values. Round your final answers to three decimal places.)

Given:

owned a pet: 547 and number of women = 300 thus n1 = 547 and x1 = 300

Did not owned a pet : 1971 and number of women = 982 , thus n2 = 1971 and x2 = 982

Find the proportion of pet owners who were women.

$\hat{p}_{1}=\frac{x_{1}}{n_{1}}=\frac{300}{547}=0.548$

and

Find the proportion of NON-pet owners who were women.